Principle:
In ecological field surveys, the quadrat sampling technique serves as a fundamental method for estimating community composition. Some sample must be collected in a given area by this method. According to the Law of Probability, the study's margin of error is minimized as the number of quadrats used for sampling increases. Based on population density, one can calculate the species diversity of the community using the Shannon Diversity Index.
Requirement: The investigation utilizes an optimized quadrat dimension applied to a hypothetical community model, which comprises seven distinct species exhibiting a stochastic (random) spatial distribution across the study area.
Procedure:
- Choice of sample area which contain randomly four species a, b, c, d, r, s & t.
- Chosen quadrate size is 1cm x1cm & number of quadrate is given to the area is as 1,2,3,4.....,10.
- Calculation of total number of each species in the sample.
- Tabulate all the figures for calculating population density & Shannon-Weiner diversity index.
The Shannon diversity index is calculated by H’ or Hs = -∑(niN)ln(ni/N)
Or H’ or Hs = - ∑pi ln pi
where ,
ni= number of individuals of i th species.
N= Total for all the species.
Pi=Relative abundance (proportion) of the i th species.
ln =Natural logarithm.
Hypothetical community data
A forest floor area was sampled using 10 quadrates of 1m2 each
Species:
a = Black-kneed Meadow
Katydid [Conocephalus melaenus]
b = Weaver ant [Oecophylla smaragdina ]
c = Red Pumpkin beetle [Aulacophora foveicollis ]
d =Hover fly [Episyrphus sp]
r = Fire ant [Solenopsis geminata]
s = Indian Black ant [Camponotus compressus ]
t = Common Cricket [Acheta domesticus]
|
Species No: |
Sampling number |
Total Number Of Individual |
Total Number Of Sample |
Quadrates present |
Density [/m2] |
|||||||||
|
|
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
||||
|
a |
4 |
2 |
0 |
0 |
1 |
0 |
1 |
3 |
7 |
2 |
20 |
10 |
7 |
20/10=2.0 |
|
b |
0 |
2 |
5 |
6 |
3 |
2 |
2 |
5 |
3 |
3 |
31 |
10 |
9 |
31/10=3.1 |
|
c |
7 |
5 |
5 |
0 |
2 |
0 |
2 |
0 |
3 |
1 |
25 |
10 |
7 |
25/10=2.5 |
|
d |
0 |
1 |
2 |
0 |
0 |
0 |
0 |
4 |
0 |
0 |
7 |
10 |
3 |
7/10=0.7 |
|
r |
4 |
0 |
0 |
0 |
2 |
0 |
10 |
22 |
0 |
0 |
38 |
10 |
4 |
38/10=3.8 |
|
s |
0 |
0 |
1 |
6 |
0 |
0 |
0 |
0 |
15 |
0 |
22 |
10 |
3 |
22/10=2.2 |
|
t |
1 |
3 |
2 |
0 |
0 |
2 |
0 |
0 |
0 |
2 |
10 |
10 |
5 |
10/10=1.0 |
|
Species |
Number
of
Individual |
Pi |
Pi
ln |
Pi
ln Pi |
|
a |
20 |
20/153=0.13 |
-0.886 |
0.13(-0.886)
= -0.11518
|
|
b |
31 |
31/153=0.20 |
-0.698 |
0.20
(-0.698) = -0.1396
|
|
c |
25 |
25/153=0.16 |
-0.7958 |
0.16
(-0.7958) = -0.127328
|
|
d |
7 |
7/153=0.045 |
-1.346 |
0.045
(-1.346 )= -0.06057 |
|
r |
38 |
38/153=0.25 |
-0.602 |
0.25
(-0.602)= -0.1505 |
|
s |
22 |
22/153=0.14 |
-0.853 |
0.14(-0.853)=
-0.11942 |
|
t |
10 |
10/153=0.065 |
-1.1870 |
0.065(-1.1870)=
-0.077155 |
|
Total |
153 |
|
|
( Σ)= -0.789753 |
The Evenness Index is calculated as:
Where H max = ln(S), and S= total number of species.
This indicates a near-homogeneous distribution of individuals across the identified taxa.
No single species is dominating the environment.
Lack of competitive exclusion, i.e. low level of future community & ecosystem service disruption.
The individuals are distributed very equally among the different species present.
The habitat in this hypothetical model provides stable, shared resources that support all seven species nearly equally.
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